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Find the Angles Between the Following Pair of Straight Lines: X − 4y = 3 and 6x − Y = 11

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Question

Find the angles between the following pair of straight lines:

x − 4y = 3 and 6x − y = 11

Answer in Brief
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Solution

The equations of the lines are
x − 4y = 3          ... (1)
6x − y = 11        ... (2)
Let \[m_1 \text { and } m_2\] be the slopes of these lines.

\[m_1 = \frac{1}{4}, m_2 = 6\]

Let \[\theta\] be the angle between the lines.
Then,

\[\tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right|\]

\[ = \left| \frac{\frac{1}{4} - 6}{1 + \frac{3}{2}} \right|\]

\[ = \frac{23}{10}\]

\[ \Rightarrow \theta = \tan^{- 1} \left( \frac{23}{10} \right)\]

Hence, the acute angle between the lines is \[\tan^{- 1} \left( \frac{23}{10} \right)\].

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Chapter 23: The straight lines - Exercise 23.13 [Page 99]

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R.D. Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.13 | Q 1.4 | Page 99

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