English

How can you find the following? Displacement from velocity – time graph.

Advertisements
Advertisements

Question

How can you find the following?

Displacement from velocity – time graph.

Graph
Advertisements

Solution

Displacement from velocity – time graph:  Displacement covered by a body is equal to the area under velocity – time graph. When an object moves with a uniform velocity, the velocity – time graph is a straight line (PQ) parallel to the time axis.

Take any two points A and B on velocity – time  graph.
From A and B, draw two perpendiculars AD and BC on the time axis such that
OD = t1 and OC = t2
Let OP = AD = BC = v = Velocity of the body.
Area under velocity – time graph = Area of rectangle ABCD
= AD × DC = v × (OC − OD) = v (t2 − t1)
= Displacement covered by the body

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Motion in One Dimension - Unit II Exercise 2 (B) Subjective Questions

APPEARS IN

Goyal Brothers Prakashan A New Approach to ICSE Physics [English] Class 9
Chapter 2 Motion in One Dimension
Unit II Exercise 2 (B) Subjective Questions | Q 3.3

RELATED QUESTIONS

The numerical ratio of displacement to distance for a moving object is :


The minimum distance between the start and finish points of the motion of an object is called the ______ of the object.


Differentiate between distance and displacement.


A body at rest is made to fall from the top of a tower. Its displacement at different instants is given in the following table: 

Time (in s) 0.1 0.2 0.3 0.4 0.5 0.6
Displacement (in m) 0.05 0.20 0.45 0.80 1.25 1.80

Draw a displacement-time graph and state whether the motion is uniform or non-uniform?


Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.

Compare the distance travelled in part BC with the distance travelled in part AB.


Figure shows the velocity-time graph of a particle moving in a straight line.

(i) State the nature of motion of particle.

(ii) Find the displacement of particle at t = 6 s.

(iii) Does the particle change its direction of motion?

(iv) Compare the distance travelled by the particle from 0 to 4 s and from 4 s to 6 s.

(v) Find the acceleration from 0 to 4 s and retardation from 4 s to 6 s.


Write two differences between distance and displacement.


The table below shows the distance travelled by two vehicles A and B during each second:

Time (s) 0 1 2 3 4 5 6 7
Distance travelled by A (m) 0 20 80 180 240 300 360 420
Distance travelled by B (m) 0 10 40 90 160 250 360 490

At what time do A and B meet?Which vehicle is moving with a constant acceleration?


Which of the following is correct?


Give one example where the displacement is zero but the distance travelled is not zero.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×