Advertisements
Advertisements
प्रश्न
How can you find the following?
Displacement from velocity – time graph.
Advertisements
उत्तर
Displacement from velocity – time graph: Displacement covered by a body is equal to the area under velocity – time graph. When an object moves with a uniform velocity, the velocity – time graph is a straight line (PQ) parallel to the time axis.
Take any two points A and B on velocity – time graph.
From A and B, draw two perpendiculars AD and BC on the time axis such that
OD = t1 and OC = t2
Let OP = AD = BC = v = Velocity of the body.
Area under velocity – time graph = Area of rectangle ABCD
= AD × DC = v × (OC − OD) = v (t2 − t1)
= Displacement covered by the body
APPEARS IN
संबंधित प्रश्न
If on a round trip you travel 6 km and then arrive back home :
What distance have you travelled ?
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
State how is the distance travelled in any part determined from this graph .
A car travels a distance 100 m with constant acceleration and average velocity of 20 ms-1. The final velocity acquired by the car is 25 ms-1.
Find
(i) The initial velocity.
(ii) Acceleration of the car.
Can distance covered by a body be less than the magnitude of its displacement?
Calculate the distance and displacement in the following case:
Is distance covered during nth second more than the distance covered in n seconds?
An object covers a distance of S meters in t seconds as follows :
| S (meters) | 0 | 8 | 20 | 20 | 16 | 10 | 0 |
| t (Seconds) | 80 | 2 | 5 | 10 | 12 | 15 | 10 |
Plot a graph, taking t on X-axis and S on Y-axis. Determine the velocity of the object at time
(i) 6 s, and
(ii) 14 s.
Displacement / Time : Velocity :: Speed / Time : ______.
A car starts from rest and moves along the x-axis with constant acceleration 5 ms–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?
The rate of change of displacement ______.
