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प्रश्न
How can you find the following?
Displacement from velocity – time graph.
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उत्तर
Displacement from velocity – time graph: Displacement covered by a body is equal to the area under velocity – time graph. When an object moves with a uniform velocity, the velocity – time graph is a straight line (PQ) parallel to the time axis.
Take any two points A and B on velocity – time graph.
From A and B, draw two perpendiculars AD and BC on the time axis such that
OD = t1 and OC = t2
Let OP = AD = BC = v = Velocity of the body.
Area under velocity – time graph = Area of rectangle ABCD
= AD × DC = v × (OC − OD) = v (t2 − t1)
= Displacement covered by the body
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संबंधित प्रश्न
Can displacement be zero even if the distance is not zero? Give one example to explain your answer.
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Compare the distance travelled in part BC with the distance travelled in part AB.
Draw displacement – time graph for the following situation:
When a body is moving with variable velocity.
Under what condition is the displacement of a body equal to the distance traveled by it?
Calculate the distance and displacement in the following case:
A satellite makes a complete round along its circular orbit. What is its displacement?
The shortest distance between two places is ______.
Match the following.
| 1. | Displacement | Knot |
| 2. | Light travelling through vacuum | Geometric centre |
| 3. | Speed of ship | Metre |
| 4. | Centre of gravity of geometrical shaped objects | Larger base area |
| 5. | Stability | Uniform velocity |
Distinguish distance and displacement.
An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height of 100 m. What is the difference in their heights after 2s if both the objects drop with the same accelerations? How does the difference in heights vary with time?
