Question

Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.

Compare the distance travelled in part BC with the distance travelled in part AB.

Answer 1

Distance travelled in part BC = Area of the rectangle tBC2t = base × height.

 = (2t - t) × v_o

 = v_ot

Distance travelled in part AB = Area of the triangle ABt

 = (1/2) × base × height

 = (1/2) × t × v_o

 = (1/2) v_o t

Therefore, distance travelled in part BC:distance travelled in part AB :: 2:1.