मराठी

Figure Given Below Shows a Velocity-time Graph for a Car Starting from Rest. the Graph Has Three Parts Ab, Bc and Cd. Compare the Distance Travelled in Part Bc with the Distance Trav

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प्रश्न

Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.

Compare the distance travelled in part BC with the distance travelled in part AB.

टीपा लिहा
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उत्तर

Distance travelled in part BC = Area of the rectangle tBC2t = base × height.

 = (2t - t) × vo

 = vot

Distance travelled in part AB = Area of the triangle ABt

 = (1/2) × base × height

 = (1/2) × t × vo

 = (1/2) vo t

Therefore, distance travelled in part BC:distance travelled in part AB :: 2:1.

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पाठ 2: Motion in One Dimension - Exercise 2 (B) [पृष्ठ ५०]

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सेलिना Concise Physics [English] Class 9 ICSE
पाठ 2 Motion in One Dimension
Exercise 2 (B) | Q 9.2 | पृष्ठ ५०

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Fill in the boxes.

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