Advertisements
Advertisements
Question
Give a simple chemical test to distinguish between the following pair of compounds:
Benzoic acid and Ethyl benzoate
Advertisements
Solution
Benzoic acid in reaction with sodium bicarbonate liberates CO2 gas with vigorous effervescence, whereas ethyl benzoate does not.
APPEARS IN
RELATED QUESTIONS
Distinguish between: CH3COOH and HCOOH
A and B are two functional isomers of compound C3H6O.On heating with NaOH and I2, isomer B forms yellow precipitate of iodoform whereas isomer A does not form any precipitate. Write the formulae of A and B.
Predict the products of the following reactions :
Give a simple chemical test to distinguish between the following pair of compounds :
CH3CH2CHO and CH3CH2COCH3
Propanal and Propanone
How will you convert ethanal into the following compound?
But-2-enoic acid
Give a simple chemical test to distinguish between the following pair of compounds:
Acetophenone and Benzophenone
Alkenes decolourise bromine water in presence of CCl4 due to formation of ______.
Which of the following compounds will give butanone on oxidation with alkaline \[\ce{KMnO4}\] solution?
Oxidation of ketones involves carbon-carbon bond cleavage. Name the products formed on oxidation of 2, 5-dimethylhexan-3-one.
Which of the following compounds gives a positive Tollen's test but negative Fehling's test?
Acetone and acetaldehyde are differentiated by
Acetaldehyde cannot show?
The reagent that can be used to distinguish acetophenone and benzophenone is ______.
An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and glycol. 'A' forms a dioxime with hydroxylamine and gives a positive iodoform and Tollen's test. Identify 'A' and give its reaction for iodoform and Tollen's test.
Benzaldehyde is obtained from Rosenmund’s reduction of:
Match List-I with List-II:
| List-I (Reaction) |
List-II (Reagents/Condition) |
||
| A. |  |
I. |  |
| B. |  |
II. | CrO3 |
| C. |  |
III. | KMnO4/KOH, Δ |
| D. |  |
IV. | (i) O3 (ii) Zn-H2O |
Choose the correct answer from the options given below:
