Advertisements
Advertisements
Question
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
Advertisements
Solution
a. A is an alkene.
B is an aldehyde with –CH3 group.
C is a methyl ketone.
b. \[\ce{CH3CHO + [Ag(NH3)2]^{+} + OH^{-} -> CH3COO^{-} + Ag + NH3 + H2O}\]
c. \[\ce{CH3COCH3 + NaOH + I2 -> CHl3 + CH3COONa}\]
d. A: CH(CH3) = C(CH3)2, B: CH3CHO, C: O = C(CH3)2
\[\begin{array}{cc}
\ce{CH3COCH3 + CH3CHO}\phantom{............................................................................}\\
\ce{↓ Ba(OH)2}\phantom{.....................................................................}\\
\phantom{}\ce{(CH3)2C(OH)CH2COCH3 + CH3CH(OH)CH2CHO + (CH3)2C(OH)CH2CHO + CH3CH(OH)CH2COCH3}\\
\ce{↓ Heat}\phantom{.........................................................................}\\
\ce{(CH3)2C = CHCOCH3 + CH3CH = CHCHO + (CH3)2C = CHCHO + CH3CH = CHCOCH3}\phantom{............}
\end{array}\]
APPEARS IN
RELATED QUESTIONS
Give a simple chemical test to distinguish between the following pair of compounds:
Ethanal and Propanal
Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
Complete the synthesis by giving missing starting material, reagent or product.

Alkenes decolourise bromine water in presence of CCl4 due to formation of ______.
Acetone and acetaldehyde are differentiated by
Acetaldehyde cannot show?
In Tollen's test for aldehyde, the overall number of electrons(s) transferred to the Tollen's reagent formula \[\ce{[Ag(NH3)2]+}\] per aldehyde group to form silver mirror is ______. (Round off to the nearest integer)
You are given four organic compounds “A”, “B” , “C” and “D”. The compounds “A”, “B” and “C” form an orange-red precipitate with 2, 4 DNP reagent. Compounds “A” and “B” reduce Tollen’s reagent while compounds “C” and “D” do not. Both “B” and “C” give a yellow precipitate when heated with iodine in the presence of NaOH. Compound “D” gives brisk effervescence with sodium bicarbonate solution. Identify “A”, “B”, “C” and “D” given the number of carbon atoms in three of these carbon compounds is three while one has two carbon atoms. Give an explanation for our answer.
Benzaldehyde is obtained from Rosenmund’s reduction of:
