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प्रश्न
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
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उत्तर
a. A is an alkene.
B is an aldehyde with –CH3 group.
C is a methyl ketone.
b. \[\ce{CH3CHO + [Ag(NH3)2]^{+} + OH^{-} -> CH3COO^{-} + Ag + NH3 + H2O}\]
c. \[\ce{CH3COCH3 + NaOH + I2 -> CHl3 + CH3COONa}\]
d. A: CH(CH3) = C(CH3)2, B: CH3CHO, C: O = C(CH3)2
\[\begin{array}{cc}
\ce{CH3COCH3 + CH3CHO}\phantom{............................................................................}\\
\ce{↓ Ba(OH)2}\phantom{.....................................................................}\\
\phantom{}\ce{(CH3)2C(OH)CH2COCH3 + CH3CH(OH)CH2CHO + (CH3)2C(OH)CH2CHO + CH3CH(OH)CH2COCH3}\\
\ce{↓ Heat}\phantom{.........................................................................}\\
\ce{(CH3)2C = CHCOCH3 + CH3CH = CHCHO + (CH3)2C = CHCHO + CH3CH = CHCOCH3}\phantom{............}
\end{array}\]
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संबंधित प्रश्न
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Give a simple chemical test to distinguish between the following pair of compounds:
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Which sugar does not reduce Fehling's solution?
An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and glycol. 'A' forms a dioxime with hydroxylamine and gives a positive iodoform and Tollen's test. Identify 'A' and give its reaction for iodoform and Tollen's test.
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Benzaldehyde is obtained from Rosenmund’s reduction of:
Match List-I with List-II:
| List-I (Reaction) |
List-II (Reagents/Condition) |
||
| A. |  |
I. |  |
| B. |  |
II. | CrO3 |
| C. |  |
III. | KMnO4/KOH, Δ |
| D. |  |
IV. | (i) O3 (ii) Zn-H2O |
Choose the correct answer from the options given below:
