मराठी

A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C).

Advertisements
Advertisements

प्रश्न

A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.

  1. Identify (A), (B) and (C).
  2. Write the reaction of B with Tollen’s reagent.
  3. Write the equation for iodoform test for C.
  4. Write down the equation for aldol condensation reaction of B and C.
टीपा लिहा
Advertisements

उत्तर

a. A is an alkene.

B is an aldehyde with –CH3 group.

C is a methyl ketone.

b. \[\ce{CH3CHO + [Ag(NH3)2]^{+} + OH^{-} -> CH3COO^{-} + Ag + NH3 + H2O}\]

c. \[\ce{CH3COCH3 + NaOH + I2 -> CHl3 + CH3COONa}\]

d. A: CH(CH3) = C(CH3)2, B: CH3CHO, C: O = C(CH3)2

\[\begin{array}{cc}
\ce{CH3COCH3 + CH3CHO}\phantom{............................................................................}\\
\ce{↓ Ba(OH)2}\phantom{.....................................................................}\\
\phantom{}\ce{(CH3)2C(OH)CH2COCH3 + CH3CH(OH)CH2CHO + (CH3)2C(OH)CH2CHO + CH3CH(OH)CH2COCH3}\\
\ce{↓ Heat}\phantom{.........................................................................}\\
\ce{(CH3)2C = CHCOCH3 + CH3CH = CHCHO + (CH3)2C = CHCHO + CH3CH = CHCOCH3}\phantom{............}
\end{array}\]

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
2022-2023 (March) Sample

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्‍न

Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?


Acetaldehyde cannot show?


Fehilng's test is positive for


Which of the following tests/reactions is given by aldehydes as well as ketones?


Write chemical test to distinguish between the following compounds:

Phenol and Benzoic acid


An organic compound neither reacts with neutral ferric chloride solution nor with Fehling solution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:


The correct set of products obtained in the following reactions:

  1. \[\ce{RCN ->[reduction]}\]
  2. \[\ce{RCN ->[(i) CH3MgBr][(ii) H2O]}\]
  3. \[\ce{RNC ->[hydrolysis]}\]
  4. \[\ce{RNH2 ->[HNO2]}\]

An organic compound 'A' with molecular formula C5H8O2 is reduced to n-pentane with hydrazine followed by heating with NaOH and glycol. 'A' forms a dioxime with hydroxylamine and gives a positive iodoform and Tollen's test. Identify 'A' and give its reaction for iodoform and Tollen's test.


An organic compound 'A' with the molecular formula C4H8O2 undergoes acid hydrolysis to form two compounds 'B' and 'C'. Oxidation of 'C' with acidified potassium permanganate also produces 'B'. Sodium salt of 'B' on heating with soda lime gives methane.

  1. Identify 'A', 'B' and 'C'.
  2. Out of 'B' and 'C', which will have higher boiling point? Give reason.

Match List-I with List-II:

  List-I
(Reaction)
  List-II
(Reagents/Condition)
A. I.
B. II. CrO3
C. III. KMnO4/KOH, Δ
D. IV. (i) O3 (ii) Zn-H2O

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×