Advertisements
Advertisements
प्रश्न
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
Advertisements
उत्तर
a. A is an alkene.
B is an aldehyde with –CH3 group.
C is a methyl ketone.
b. \[\ce{CH3CHO + [Ag(NH3)2]^{+} + OH^{-} -> CH3COO^{-} + Ag + NH3 + H2O}\]
c. \[\ce{CH3COCH3 + NaOH + I2 -> CHl3 + CH3COONa}\]
d. A: CH(CH3) = C(CH3)2, B: CH3CHO, C: O = C(CH3)2
\[\begin{array}{cc}
\ce{CH3COCH3 + CH3CHO}\phantom{............................................................................}\\
\ce{↓ Ba(OH)2}\phantom{.....................................................................}\\
\phantom{}\ce{(CH3)2C(OH)CH2COCH3 + CH3CH(OH)CH2CHO + (CH3)2C(OH)CH2CHO + CH3CH(OH)CH2COCH3}\\
\ce{↓ Heat}\phantom{.........................................................................}\\
\ce{(CH3)2C = CHCOCH3 + CH3CH = CHCHO + (CH3)2C = CHCHO + CH3CH = CHCOCH3}\phantom{............}
\end{array}\]
APPEARS IN
संबंधित प्रश्न
A and B are two functional isomers of compound C3H6O.On heating with NaOH and I2, isomer B forms yellow precipitate of iodoform whereas isomer A does not form any precipitate. Write the formulae of A and B.
Give a simple chemical test to distinguish between the following pair of compounds :
CH3CH2CHO and CH3CH2COCH3
Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
Give a simple chemical test to distinguish between the following pair of compounds:
Pentan-2-one and Pentan-3-one
Oxidation of ketones involves carbon-carbon bond cleavage. Name the products formed on oxidation of 2, 5-dimethylhexan-3-one.
What is the composition of Fehling's reagent?
The major products formed in the following reaction sequence A and B are:

An organic compound neither reacts with neutral ferric chloride solution nor with Fehling solution. It however, reacts with Grignard reagent and gives positive iodoform test. The compound is:
An organic compound 'A' with the molecular formula C4H8O2 undergoes acid hydrolysis to form two compounds 'B' and 'C'. Oxidation of 'C' with acidified potassium permanganate also produces 'B'. Sodium salt of 'B' on heating with soda lime gives methane.
- Identify 'A', 'B' and 'C'.
- Out of 'B' and 'C', which will have higher boiling point? Give reason.
Benzaldehyde is obtained from Rosenmund’s reduction of:
