Advertisements
Advertisements
Question
Give a simple chemical test to distinguish between the following pair of compounds:
Phenol and Benzoic acid
Advertisements
Solution 1
Phenol and benzoic acid can be distinguished by ferric chloride test. In the ferric chloride test, phenol reacts with neutral FeCl3 to make an iron-phenol complex that turns violet.
\[\ce{\underset{Phenol}{6C6H5OH} + FeCl3 -> \underset{(Violet colour)}{\underset{Iron-phenol complex}{[Fe(OC6H5)6]^3-}} + 3H+ + 3Cl-}\]
But benzoic acid reacts with neutral FeCl3 to give a buff coloured ppt. of ferric benzoate.
\[\ce{\underset{Benzoic acid}{3C6H5OH} + FeCl3 ->\underset{(Buff coloured ppt)}{\underset{Ferric benzoate}{(C6H5COO)3Fe}} + 3HCl}\]
Solution 2
Benzoic acid reacts with NaHCO3 to release CO2 gas with effervescence, whereas phenol does not.

Phenol Br2 decolourises water to give white precipitate but does not give benzoic acid.

APPEARS IN
RELATED QUESTIONS
Distinguish between:
C6H5-COCH3 and C6H5-CHO
Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
Give a simple chemical test to distinguish between the following pair of compounds:
Benzaldehyde and Acetophenone
An organic compound contains 69.77% carbon, 11.63% hydrogen and rest oxygen. The molecular mass of the compound is 86. It does not reduce Tollens’ reagent but forms an addition compound with sodium hydrogensulphite and give positive iodoform test. On vigorous oxidation it gives ethanoic and propanoic acid. Write the possible structure of the compound.
Complete the synthesis by giving missing starting material, reagent or product.

Oxidation of ketones involves carbon-carbon bond cleavage. Name the products formed on oxidation of 2, 5-dimethylhexan-3-one.
Which of the following compounds gives a positive Tollen's test but negative Fehling's test?
Which sugar does not reduce Fehling's solution?
Solvent used for dewaxing of petroleum products are
Acetone and acetaldehyde are differentiated by
Ammonical silver nitrate solution is called
A hydrocarbon (A) with molecular formula C5H10 on ozonolysis gives two products (B) and (C). Both (B) and (C) give a yellow precipitate when heated with iodine in presence of NaOH while only (B) give a silver mirror on reaction with Tollen’s reagent.
- Identify (A), (B) and (C).
- Write the reaction of B with Tollen’s reagent.
- Write the equation for iodoform test for C.
- Write down the equation for aldol condensation reaction of B and C.
The correct set of products obtained in the following reactions:
- \[\ce{RCN ->[reduction]}\]
- \[\ce{RCN ->[(i) CH3MgBr][(ii) H2O]}\]
- \[\ce{RNC ->[hydrolysis]}\]
- \[\ce{RNH2 ->[HNO2]}\]
Choose the reaction which is not possible:
In Tollen's test for aldehyde, the overall number of electrons(s) transferred to the Tollen's reagent formula \[\ce{[Ag(NH3)2]+}\] per aldehyde group to form silver mirror is ______. (Round off to the nearest integer)
An organic compound 'A' with the molecular formula C4H8O2 undergoes acid hydrolysis to form two compounds 'B' and 'C'. Oxidation of 'C' with acidified potassium permanganate also produces 'B'. Sodium salt of 'B' on heating with soda lime gives methane.
- Identify 'A', 'B' and 'C'.
- Out of 'B' and 'C', which will have higher boiling point? Give reason.
