English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Give a simple chemical test to distinguish between the following pair of compounds: Pentan-2-one and Pentan-3-one

Advertisements
Advertisements

Questions

Give a simple chemical test to distinguish between the following pair of compounds:

Pentan-2-one and Pentan-3-one

Can you distinguish pentan-2-one and pentan-3-one by iodoform test?

Chemical Equations/Structures
Distinguish Between
Advertisements

Solution

Pentan-2-one and pentan-3-one can be distinguished by the iodoform test.

Iodoform test: Pentan-2-one is a methyl ketone, so it responds to the iodoform test. However, pentan-3-one is not a methyl ketone and does not respond to this test. 

Pentan-2-one has a methyl ketone group (CH3-CO-) at the second carbon. Compounds with a methyl ketone group give a positive iodoform test, producing a yellow precipitate of iodoform (CHI3).

\[\begin{array}{cc}
\ce{O}\phantom{.................................................}\\
||\phantom{.................................................}\\
\ce{\underset{Pentan-2-one}{CH3CH2CH2 - C - CH3} + 3NaOI ->\underset{Sodium butanoate}{CH3CH2CH2COONa} + \underset{(yellow ppt)}{\underset{Iodoform}{CHI3\downarrow}} + 2NaOH}\
\end{array}\]

Pentan-3-one has the carbonyl group at the third position, so it does not have a methyl ketone structure. It does not give a positive iodoform test.

\[\begin{array}{cc}
\ce{O}\phantom{.......................................}\\
||\phantom{.......................................}\\
\ce{\underset{Pentan-3-one}{CH3CH2 - C - CH2CH3} + NaOI -> No yellow ppt of iodoform}\
\end{array}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 8: Aldehydes, Ketones and Carboxylic Acids - Exercises [Page 256]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 8 Aldehydes, Ketones and Carboxylic Acids
Exercises | Q 8.13 (v) | Page 256
Nootan Chemistry [English] Class 12 ISC
Chapter 6 Haloalkanes and Haloarenes
SHORT ANSWER TYPE QUESTIONS | Q 31. (c) | Page 611

RELATED QUESTIONS

Distinguish between:

C6H5-COCH3 and C6H5-CHO


Predict the products of the following reactions :


An organic compound contains 69.77% carbon, 11.63% hydrogen and rest oxygen. The molecular mass of the compound is 86. It does not reduce Tollens’ reagent but forms an addition compound with sodium hydrogensulphite and give positive iodoform test. On vigorous oxidation it gives ethanoic and propanoic acid. Write the possible structure of the compound.


Which of the following compounds will give butanone on oxidation with alkaline \[\ce{KMnO4}\] solution?


Oxidation of ketones involves carbon-carbon bond cleavage. Name the products formed on oxidation of 2, 5-dimethylhexan-3-one.


Which sugar does not reduce Fehling's solution?


Acetaldehyde cannot show?


What is the composition of Fehling's reagent?


Which among the above compound/s does/do not form Silver mirror when treated with Tollen's reagent?


The major products formed in the following reaction sequence A and B are:


Choose the reaction which is not possible: 


The reagent that can be used to distinguish acetophenone and benzophenone is ______.


An organic compound 'A' with the molecular formula C4H8O2 undergoes acid hydrolysis to form two compounds 'B' and 'C'. Oxidation of 'C' with acidified potassium permanganate also produces 'B'. Sodium salt of 'B' on heating with soda lime gives methane.

  1. Identify 'A', 'B' and 'C'.
  2. Out of 'B' and 'C', which will have higher boiling point? Give reason.

Benzaldehyde is obtained from Rosenmund’s reduction of:


Match List-I with List-II:

  List-I
(Reaction)
  List-II
(Reagents/Condition)
A. I.
B. II. CrO3
C. III. KMnO4/KOH, Δ
D. IV. (i) O3 (ii) Zn-H2O

Choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×