Advertisements
Advertisements
Question
Distinguish between: CH3COOH and HCOOH
Advertisements
Solution
Formic acid gives the silver mirror test on treating with ammoniacal silver nitrate. Acetic acid does not give this test.
HCOOH + 2[Ag (NH3)2] NO3 →2Ag + CO2 + 2NH4NO3 + 2NH3
APPEARS IN
RELATED QUESTIONS
Give a simple chemical test to distinguish between the following pair of compounds:
Ethanal and Propanal
Give a simple chemical test to distinguish between the following pair of compounds :
CH3CH2CHO and CH3CH2COCH3
Out of CH3CH2 – CO – CH2 – CH3 and CH3CH2 – CH2 – CO – CH3, which gives iodoform test?
How will you convert ethanal into the following compound?
But-2-enoic acid
Acetaldehyde cannot show?
Ammonical silver nitrate solution is called
Write chemical test to distinguish between the following compounds:
Phenol and Benzoic acid
What is the composition of Fehling's reagent?
In Tollen's test for aldehyde, the overall number of electrons(s) transferred to the Tollen's reagent formula \[\ce{[Ag(NH3)2]+}\] per aldehyde group to form silver mirror is ______. (Round off to the nearest integer)
Match List-I with List-II:
| List-I (Reaction) |
List-II (Reagents/Condition) |
||
| A. | ![]() |
I. | ![]() |
| B. | ![]() |
II. | CrO3 |
| C. | ![]() |
III. | KMnO4/KOH, Δ |
| D. | ![]() |
IV. | (i) O3 (ii) Zn-H2O |
Choose the correct answer from the options given below:





