Advertisements
Advertisements
Question
From the velocity – time graph given below, calculate deceleration in region BC.
Advertisements
Solution
Deceleration in the region B = +Slope of v.t. graph from B to C
= `"BG"/"GC"=(14-6)/(16-12)=8/4` = 2 ms−2
APPEARS IN
RELATED QUESTIONS
The unit of retardation is ____________
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
(a) Is the magnitude of acceleration higher or lower than that of retardation ? Give a reason .
(b) Compare the magnitude of acceleration and retardation .
If a body is moving with a constant velocity its acceleration is ______.
Draw velocity – time graph for the following situation:
When a body is moving with variable velocity, but uniform retardation.
Define acceleration.
The acceleration of a moving body is constant in magnitude and direction. Must the path of the body be a straight line?
If not, given an example.
Out of energy and acceleration, which one is a vector?
Figure represents graphically the velocity of a car moving along a straight road over a period of 100 hours.
Calculate the acceleration along AB and the retardation along BC.
Assertion: A positive acceleration of a body can be associated with the slowing down of the body.
Reason: Acceleration is a vector.
