Advertisements
Advertisements
प्रश्न
From the velocity – time graph given below, calculate deceleration in region BC.

Advertisements
उत्तर
Deceleration in the region B = +Slope of v.t. graph from B to C
= `"BG"/"GC"=(14-6)/(16-12)=8/4` = 2 ms−2
APPEARS IN
संबंधित प्रश्न
Figure shows the velocity-time graphs for two cars A and B moving in the same direction. Which car has greater acceleration? Give reasons to your answer.

A bullet initially moving with a velocity 20 m/s strikes a target and comes to rest after penetrating a distance 10 cm into the target. Calculate the retardation caused by the target.
A ball is rolling from A to D on a flat and smooth surface. Its speed is 2 cm/s. On reaching B, it was pushed continuously up to C. On reaching D from C, its speed had become 4 cm/s. It took 2 seconds for it to go from B to C. What is the acceleration of the ball as it goes from B to C?

A motor bike running at 5 ms−1, picks up a velocity of 30 ms−1 in 5s. Calculate
- acceleration
- distance covered during acceleration.
Write the SI unit of retardation.
Can you use the relation [B1]?
State if the following situation is possible:
A body moving with a constant velocity in an accelerated motion.
Figure represents graphically the velocity of a car moving along a straight road over a period of 100 hours.
Calculate the acceleration along AB and the retardation along BC.
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
What is the difference between uniform acceleration and non–uniform acceleration?
