Advertisements
Advertisements
प्रश्न
From the velocity – time graph given below, calculate Distance covered in the region ABCE.

Advertisements
उत्तर
Distance covered in region ABCE = ar(ΔABF) + area of trapezium BCEF
= `1/2xx"AF"xx"BF"+1/2("BF+CF")xx"GC"`
= `1/2xx12xx14+1/2(14+6)xx4`
= 6 × 14 + 10 × 4
= 84 + 40
= 124 m
APPEARS IN
संबंधित प्रश्न
Draw a velocity-time graph to show the following motion :
A car accelerates uniformly from rest for 5 s ; then it travels at a steady’ velocity for 5 s.
What type of motion is represented by the following graph ?

What does the slope of a displacement-time graph represent?
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.

In which section, car has a zero acceleration?
A ball is thrown up vertically and returns back to thrower in 6 s. Assuming there is no air friction, plot a graph between velocity and time. From the graph calculate
- deceleration
- acceleration
- total distance covered by ball
- average velocity.
Given on th e side are a few speed - time graphs for various objects moving along a stra ight line. Refer below figure. (a), (b), (c) and (d).
Which of these graphs represent
(a) Uni form motion
(b) Motion with speed increasing
(c) Motion with speed decreasing and
(d) Motion with speed oscillating.?
Draw the following graph:
Speed versus time for a non-uniform acceleration.
Its time-displacement graph is a straight line.
Draw distance-time graph to show:
Decreasing velocity
State whether true or false. If false, correct the statement.
The velocity – time graph of a particle falling freely under gravity would be a straight line parallel to the x axis.
