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प्रश्न
From the velocity – time graph given below, calculate Distance covered in the region ABCE.

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उत्तर
Distance covered in region ABCE = ar(ΔABF) + area of trapezium BCEF
= `1/2xx"AF"xx"BF"+1/2("BF+CF")xx"GC"`
= `1/2xx12xx14+1/2(14+6)xx4`
= 6 × 14 + 10 × 4
= 84 + 40
= 124 m
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संबंधित प्रश्न
A train starting from rest picks up a speed of 20 ms−1 in 200 s. It continues to move at the same rate for the next 500 s and is then brought to rest in another 100 s.
- Plot a speed-time graph.
- From graph calculate
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(b) uniform rate of retardation
(c) total distance covered before stopping
(d) average speed.
A ball is thrown up vertically and returns back to thrower in 6 s. Assuming there is no air friction, plot a graph between velocity and time. From the graph calculate
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- acceleration
- total distance covered by ball
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How does the slope of a speed-time graph give the acceleration of a body moving along a straight line?
Draw the speed-time graph of a body when its initial speed is not zero and the speed increases uniformly with time.
Draw the following graph:
Speed versus time for a fluctuating speed.
Interpret the following graph:
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
How far did B travel between the time he passed C and A?

(i) In speed time graph uniform motion is given by a straight line parallel to x axis so figure (a) denotes the uniform motion.
(ii) In speed time graph motion with increasing speed is shown by straight line with positive slope so figure (c) denotes the motion with speed increasing.
(iii) In speed time graph motion with decreasing speed is shown by straight line with negative slope so figure (b) denotes the motion with speed decreasing.
(iv) In speed time graph motion with oscillating speed is shown by zigzag line so figure {d) denotes the motion with speed oscillating.
Mention the uses of the velocity-time graph.
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