Advertisements
Advertisements
प्रश्न
From the velocity – time graph given below, calculate Average velocity in region CED.
Advertisements
उत्तर
Displacement covered in region ΔCDE = area of ΔCDE
= `1/2xx"ED"xx"CE"`
= `1/2xx(28-16)xx6`
= `1/2xx12xx6`
= 36 m
Average velocity in region CED = `"Total displacement"/"Time"`
= `36/12`
= 3 ms−1
APPEARS IN
संबंधित प्रश्न
Given alongside is the velocity-time graph for a moving body :
Find :
(i) Velocity of the body at point C.
(ii) Acceleration acting on the body between A and B.
(iii) Acceleration acting on the body between B and C.
What does the slope of a displacement-time graph represent?
A body at rest is thrown downward from the top of the tower. Draw a distance – time graph of its free fall under gravity during the first 3 seconds. Show your table of values starting t = 0 with an interval of 1 second, (g = 10 ms−2).
From the velocity – time graph given below, calculate acceleration in the region AB.
Draw the speed-time graph of a body starting from some point P, gradually picking up speed, then running at a uniform speed and finally slowing down to stop at some point Q.
Figure shows the velocity-time graphs for two objects A and B moving in same direction . Which object has the greater a cceleration?
Sketch the shape of the velocity-time graph for a body moving with:
Uniformly velocity
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
Which of the three is traveling the fastest?
Figure shows the distance-time graph of three students A, B and C. On the basis of the graph, answer the following :
When B meets A, where is C?
The given graph shows the variation of velocity (v) with position (x) for a particle moving along a straight line
Which of the following graph shows the variation of acceleration (a) with position (x)?
