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प्रश्न
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC, and CD.
Is the magnitude of acceleration higher or lower than that of retardation? Give a reason.
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उत्तर
Acceleration = slope of AB = `"Bt"/"At"="v"_0/"t"` ......(i)
Retardation = slope of CD = `"v"_0/(1/2"t")=2 "v"_0/"t"` ..........(ii)
∵ Magnitude of retardation is twice the magnitude of acceleration.
∴ Magnitude of acceleration is lower.
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संबंधित प्रश्न
Show by using the graphical method that: `s=ut+1/2at^2` where the symbols have their usual meanings.
Study the speed-time graph of a car given alongside and answer the following questions:
(i) What type of motion is represented by OA ?
(ii) What type of motion is represented by AB ?
(iii) What type of motion is represented by BC ?
(iv) What is the acceleration of car from O to A ?
(v)What is the acceleration of car from A to B ?
(vi) What is the retardation of car from B to C ?
What does the slope of velocity-time graph represent?
Multiple choice Question. Select the correct option.
The distance covered in the adjoining velocity-time graph is :
Draw displacement – time graph for the following situation:
When a body is stationary.
From the velocity – time graph given below, calculate Average velocity in region CED.
The area under a speed-time graph in a given intervals gives the total distance covered by a body irrespective of its motion being uniform or non-uniform.
What can you conclude if the speed-time graph of a body is a straight line sloping upwards and not passing through the origin?
What can you say about the motion of a body if:
Its time-velocity graph is a straight line
Derive the equation
S = ut+ `1/2` at2
Using a speed- time graph
