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Question
Find the length of the perpendicular of a triangle whose base is 5cm and the hypotenuse is 13cm. Also, find its area.
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Solution
Base = 5cm, Hypotenuse = 13cm
By Pythagoras theorem,
(perpendicular)2 = (13cm)2 - (5cm)2
(perpendicular)2 = 169cm2 - 25cm2
(perpendicular)2 = 144cm2
(perpendicular)2 = (12cm)2
∴ Perpendicular = 12cm
Area of the triangle
= 13cm2 x (Base x Perpendicular)
= `(1)/(2) xx 5"cm" xx 12"cm"`
= 30cm2.
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