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Find the Length of the Perpendicular of a Triangle Whose Base is 5cm and the Hypotenuse is 13cm. Also, Find Its Area.

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प्रश्न

Find the length of the perpendicular of a triangle whose base is 5cm and the hypotenuse is 13cm. Also, find its area.

योग
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उत्तर

Base = 5cm, Hypotenuse = 13cm
By Pythagoras theorem,
(perpendicular)2 = (13cm)2 - (5cm)2
(perpendicular)2 = 169cm2 - 25cm2
(perpendicular)2 = 144cm2
(perpendicular)2 = (12cm)2
∴ Perpendicular = 12cm
Area of the triangle 
= 13cm2 x (Base x Perpendicular)

= `(1)/(2) xx 5"cm" xx 12"cm"`
= 30cm2.

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अध्याय 17: Pythagoras Theorem - Exercise 17.1

APPEARS IN

फ्रैंक Mathematics [English] Class 9 ICSE
अध्याय 17 Pythagoras Theorem
Exercise 17.1 | Q 1

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