Advertisements
Advertisements
प्रश्न
A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?
Advertisements
उत्तर
Given :
Length of ladder = 6.5 m
Length of the foot of the wall = 2.5 m
To find: Height AC According to Pythagoras Theorem,
(BC)2 = (AB)2 + (AC)2

(6.5)2 = (2.5)2 + (AC)2
42.25 = 6.25 + AC2
AC2 = 42.25 – 6.25 = 36 m
AC = `sqrt(6xx6)` = 6 m
∴ Height of wall = 6 m
APPEARS IN
संबंधित प्रश्न
If ABC is an equilateral triangle of side a, prove that its altitude = ` \frac { \sqrt { 3 } }{ 2 } a`
In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that
`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`
`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`
`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`
Identify, with reason, if the following is a Pythagorean triplet.
(5, 12, 13)
Find the value of (sin2 33 + sin2 57°)
In triangle PQR, angle Q = 90°, find: PR, if PQ = 8 cm and QR = 6 cm
In the given figure, AD = 13 cm, BC = 12 cm, AB = 3 cm and angle ACD = angle ABC = 90°. Find the length of DC.

Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AC2 - AB2 = 2BC x ED
Two poles of 10 m and 15 m stand upright on a plane ground. If the distance between the tops is 13 m, find the distance between their feet.
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
