हिंदी

In an equilateral triangle PQR, prove that PS2 = 3(QS)2.

Advertisements
Advertisements

प्रश्न

In an equilateral triangle PQR, prove that PS2 = 3(QS)2.

योग
Advertisements

उत्तर

Given: PS is the altitude of ΔPQR.

In ΔPSQ and ΔPSR,

∠PSQ ≅ ∠PSR   ......[Each angle is equal to 90°]

PS ≅ SP   ......[Common side]

PQ ≅ PR  ......[Sides of an equilateral triangle]

By R.H.S. criterion of congruence,

ΔPSQ ≅ ΔPSR

∴ QS ≅ SR  ......[C.S.C.T.]

Now, QS + SR = QR

QS + QS = QR  .......[∵ SR = QS]

2QS = QR

QS = `(QR)/2`  ......(i)

In right-angled triangle PQS, by Pythagoras theorem,

PS2 + QS2 = PQ2

PS2 + QS2 = QR2  ......[∵ PQ = QR]

PS2 = QR2 – QS2

ps2 = (2QS)2 – QS2  ......[∵ QR = 2QS]

PS2 = 4QS2 – QS2

PS2 = 3QS2 

Hence proved.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2025-2026 (March) Model set 1 by shaalaa.com

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

If ABC is an equilateral triangle of side a, prove that its altitude = ` \frac { \sqrt { 3 } }{ 2 } a`


In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that

`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`

`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`

`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`


In the following figure, O is a point in the interior of a triangle ABC, OD ⊥ BC, OE ⊥ AC and OF ⊥ AB. Show that

(i) OA2 + OB2 + OC2 − OD2 − OE2 − OF2 = AF2 + BD2 + CE2

(ii) AF2 + BD2 + CE= AE2 + CD2 + BF2


Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of remaining two sides.


Find the length diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.


In the given figure, ∠B = 90°, XY || BC, AB = 12 cm, AY = 8cm and AX : XB = 1 : 2 = AY : YC.

Find the lengths of AC and BC.


In the following figure, AD is perpendicular to BC and D divides BC in the ratio 1: 3.

Prove that : 2AC2 = 2AB2 + BC2


In triangle ABC, angle A = 90o, CA = AB and D is the point on AB produced.
Prove that DC2 - BD2 = 2AB.AD.


Triangle PQR is right-angled at vertex R. Calculate the length of PR, if: PQ = 34 cm and QR = 33.6 cm.


In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:
(i) CP
(ii) PD
(iii) CD


In the given figure, AD = 13 cm, BC = 12 cm, AB = 3 cm and angle ACD = angle ABC = 90°. Find the length of DC.


A right triangle has hypotenuse p cm and one side q cm. If p - q = 1, find the length of third side of the triangle.


The length of the diagonals of rhombus are 24cm and 10cm. Find each side of the rhombus.


In a triangle ABC right angled at C, P and Q are points of sides CA and CB respectively, which divide these sides the ratio 2 : 1.
Prove that: 9BP2 = 9BC2 + 4AC2


Find the unknown side in the following triangles


Find the distance between the helicopter and the ship


Rithika buys an LED TV which has a 25 inches screen. If its height is 7 inches, how wide is the screen? Her TV cabinet is 20 inches wide. Will the TV fit into the cabinet? Give reason


Foot of a 10 m long ladder leaning against a vertical wall is 6 m away from the base of the wall. Find the height of the point on the wall where the top of the ladder reaches.


In figure, PQR is a right triangle right angled at Q and QS ⊥ PR. If PQ = 6 cm and PS = 4 cm, find QS, RS and QR.


In a right-angled triangle ABC, if angle B = 90°, BC = 3 cm and AC = 5 cm, then the length of side AB is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×