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Question
A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?
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Solution
Given :
Length of ladder = 6.5 m
Length of the foot of the wall = 2.5 m
To find: Height AC According to Pythagoras Theorem,
(BC)2 = (AB)2 + (AC)2
(6.5)2 = (2.5)2 + (AC)2
42.25 = 6.25 + AC2
AC2 = 42.25 – 6.25 = 36 m
AC = `sqrt(6xx6)` = 6 m
∴ Height of wall = 6 m
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