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Question
In triangle ABC, line I, is a perpendicular bisector of BC.
If BC = 12 cm, SM = 8 cm, find CS
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Solution
Given l1, is the perpendicular bisector of BC.
∴ ∠SMC = 90°and BM = MC
BC = 12 cm
⇒ BM + MC = 12 cm
MC + MC = 12 cm
2MC = 12
MC = `12/2`
MC = 6 cm
Given SM = 8 cm
By Pythagoras theorem SC2 = SM2 + MC2
SC2 = 82 + 62
SC2 = 64 + 36
CS2 = 100
CS2 = 102
CS = 10 cm
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