Advertisements
Advertisements
प्रश्न
In triangle ABC, line I, is a perpendicular bisector of BC.
If BC = 12 cm, SM = 8 cm, find CS
Advertisements
उत्तर
Given l1, is the perpendicular bisector of BC.
∴ ∠SMC = 90°and BM = MC
BC = 12 cm
⇒ BM + MC = 12 cm
MC + MC = 12 cm
2MC = 12
MC = `12/2`
MC = 6 cm
Given SM = 8 cm
By Pythagoras theorem SC2 = SM2 + MC2
SC2 = 82 + 62
SC2 = 64 + 36
CS2 = 100
CS2 = 102
CS = 10 cm
APPEARS IN
संबंधित प्रश्न
In Figure ABD is a triangle right angled at A and AC ⊥ BD. Show that AC2 = BC × DC

Two poles of heights 6 m and 11 m stand vertically on a plane ground. If the distance between their feet is 12 m;
find the distance between their tips.
Find the length of diagonal of the square whose side is 8 cm.
Use the information given in the figure to find the length AD.

The sides of the triangle are given below. Find out which one is the right-angled triangle?
1.5, 1.6, 1.7
Calculate the area of a right-angled triangle whose hypotenuse is 65cm and one side is 16cm.
In a triangle ABC right angled at C, P and Q are points of sides CA and CB respectively, which divide these sides the ratio 2 : 1.
Prove that: 9BP2 = 9BC2 + 4AC2
A man goes 18 m due east and then 24 m due north. Find the distance of his current position from the starting point?
Find the unknown side in the following triangles
If the hypotenuse of one right triangle is equal to the hypotenuse of another right triangle, then the triangles are congruent.
