Advertisements
Advertisements
प्रश्न
ABC is a triangle right angled at C. If AB = 25 cm and AC = 7 cm, find BC.
Advertisements
उत्तर
By applying Pythagoras theorem in ΔABC,
(AC)2 + (BC)2 = (AB)2
(BC)2 = (AB)2 − (AC)2
(BC)2 = (25)2 − (7)2
(BC)2 = 625 − 49
(BC)2 = 576
∴ BC = 24 cm
APPEARS IN
संबंधित प्रश्न
In the following figure, O is a point in the interior of a triangle ABC, OD ⊥ BC, OE ⊥ AC and OF ⊥ AB. Show that
(i) OA2 + OB2 + OC2 − OD2 − OE2 − OF2 = AF2 + BD2 + CE2
(ii) AF2 + BD2 + CE2 = AE2 + CD2 + BF2
Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.
Find the length of the hypotenuse of a right angled triangle if remaining sides are 9 cm and 12 cm.
In ∆ABC, seg AD ⊥ seg BC, DB = 3CD.
Prove that: 2AB2 = 2AC2 + BC2
In triangle ABC, AB = AC = x, BC = 10 cm and the area of the triangle is 60 cm2.
Find x.
In triangle ABC, given below, AB = 8 cm, BC = 6 cm and AC = 3 cm. Calculate the length of OC.
Diagonals of rhombus ABCD intersect each other at point O.
Prove that: OA2 + OC2 = 2AD2 - `"BD"^2/2`
Prove that (1 + cot A - cosec A ) (1 + tan A + sec A) = 2
The length of the diagonals of rhombus are 24cm and 10cm. Find each side of the rhombus.
Two rectangles are congruent, if they have same ______ and ______.
