Advertisements
Advertisements
प्रश्न
A ladder, 6.5 m long, rests against a vertical wall. If the foot of the ladder is 2.5 m from the foot of the wall, find up to how much height does the ladder reach?
Advertisements
उत्तर
Given :
Length of ladder = 6.5 m
Length of the foot of the wall = 2.5 m
To find: Height AC According to Pythagoras Theorem,
(BC)2 = (AB)2 + (AC)2

(6.5)2 = (2.5)2 + (AC)2
42.25 = 6.25 + AC2
AC2 = 42.25 – 6.25 = 36 m
AC = `sqrt(6xx6)` = 6 m
∴ Height of wall = 6 m
APPEARS IN
संबंधित प्रश्न
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
Identify, with reason, if the following is a Pythagorean triplet.
(3, 5, 4)
In ∆ABC, ∠BAC = 90°, seg BL and seg CM are medians of ∆ABC. Then prove that:
4(BL2 + CM2) = 5 BC2

A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final position of the boy.
Find the Pythagorean triplet from among the following set of numbers.
2, 4, 5
Find the Pythagorean triplet from among the following set of numbers.
4, 7, 8
The sides of the triangle are given below. Find out which one is the right-angled triangle?
11, 12, 15
The sides of the triangle are given below. Find out which one is the right-angled triangle?
1.5, 1.6, 1.7
In an equilateral triangle ABC, the side BC is trisected at D. Prove that 9 AD2 = 7 AB2.
The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is ______.
