English

Find the Length of the Hypotenuse of a Triangle Whose Other Two Sides Are 24cm and 7cm.

Advertisements
Advertisements

Question

Find the length of the hypotenuse of a triangle whose other two sides are 24cm and 7cm.

Sum
Advertisements

Solution

The two sides (excluding hypotenuse) of a right-angled triangle are given as  24cm and 7cm
(hypotenuse)2 = (24cm)2 + (7cm)2
(hypotenuse)2 = 576cm2 + 49cm2 
(hypotenuse)2 = 625cm2 
(hypotenuse)2 = (25cm)2 
Thus, the length of the hypotenuse of the triangle is 25cm.

shaalaa.com
  Is there an error in this question or solution?
Chapter 17: Pythagoras Theorem - Exercise 17.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 17 Pythagoras Theorem
Exercise 17.1 | Q 2

RELATED QUESTIONS

If the sides of a triangle are 6 cm, 8 cm and 10 cm, respectively, then determine whether the triangle is a right angle triangle or not.


In triangle ABC, ∠C=90°. Let BC= a, CA= b, AB= c and let 'p' be the length of the perpendicular from 'C' on AB, prove that:

1. cp = ab

2. `1/p^2=1/a^2+1/b^2`


The perimeter of a triangle with vertices (0, 4), (0, 0) and (3, 0) is

(A)\[7 + \sqrt{5}\]
(B) 5
(C) 10
(D) 12


In ΔMNP, ∠MNP = 90˚, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.


A man goes 40 m due north and then 50 m due west. Find his distance from the starting point.


In the given figure, AB//CD, AB = 7 cm, BD = 25 cm and CD = 17 cm;
find the length of side BC.


In triangle ABC, AB = AC = x, BC = 10 cm and the area of the triangle is 60 cm2.
Find x.


In the following figure, AD is perpendicular to BC and D divides BC in the ratio 1: 3.

Prove that : 2AC2 = 2AB2 + BC2


In triangle ABC, ∠B = 90o and D is the mid-point of BC.

Prove that: AC2 = AD2 + 3CD2.


In the following Figure ∠ACB= 90° and CD ⊥ AB, prove that  CD2  = BD × AD


The sides of a certain triangle is given below. Find, which of them is right-triangle

16 cm, 20 cm, and 12 cm


In the given figure, angle BAC = 90°, AC = 400 m, and AB = 300 m. Find the length of BC.


A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final position of the boy.


Find the Pythagorean triplet from among the following set of numbers.

2, 6, 7


A right triangle has hypotenuse p cm and one side q cm. If p - q = 1, find the length of third side of the triangle.


In ∆PQR, PD ⊥ QR such that D lies on QR. If PQ = a, PR = b, QD = c and DR = d, prove that (a + b)(a – b) = (c + d)(c – d).


Prove that the area of the semicircle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the semicircles drawn on the other two sides of the triangle.


The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is ______.


Two squares having same perimeter are congruent.


The hypotenuse (in cm) of a right angled triangle is 6 cm more than twice the length of the shortest side. If the length of third side is 6 cm less than thrice the length of shortest side, then find the dimensions of the triangle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×