Advertisements
Advertisements
Question
In the given figure, angle BAC = 90°, AC = 400 m, and AB = 300 m. Find the length of BC.
Advertisements
Solution
AC = 400 m
AB = 300 m
BC =?
According to Pythagoras Theorem,
BC2 = AB2 + AC2
BC2 = (300)2 + (400)2
BC2 = 90000 + 160000
BC2 = 250000
BC =`sqrt250000` = 500 m
APPEARS IN
RELATED QUESTIONS
ABC is a right triangle right-angled at C. Let BC = a, CA = b, AB = c and let p be the length of perpendicular from C on AB, prove that
(i) cp = ab
`(ii) 1/p^2=1/a^2+1/b^2`
Prove that the sum of the squares of the diagonals of parallelogram is equal to the sum of the squares of its sides.
In the figure: ∠PSQ = 90o, PQ = 10 cm, QS = 6 cm and RQ = 9 cm. Calculate the length of PR.
In the following Figure ∠ACB= 90° and CD ⊥ AB, prove that CD2 = BD × AD
The sides of the triangle are given below. Find out which one is the right-angled triangle?
8, 15, 17
Find the length of the hypotenuse of a triangle whose other two sides are 24cm and 7cm.
In a square PQRS of side 5 cm, A, B, C and D are points on sides PQ, QR, RS and SP respectively such as PA = PD = RB = RC = 2 cm. Prove that ABCD is a rectangle. Also, find the area and perimeter of the rectangle.
Is the triangle with sides 25 cm, 5 cm and 24 cm a right triangle? Give reasons for your answer.
The longest side of a right angled triangle is called its ______.
The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. If the ladder is shifted in such a way that its foot is 8 m away from the wall, to what height does its top reach?
