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Question
A man goes 40 m due north and then 50 m due west. Find his distance from the starting point.
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Solution
Here, we need to measure the distance AB as shown in the figure below,
Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.
Therefore, in this case
AB2 = BC2 + CA2
AB2 = 502 + 402
AB2 = 2500 + 1600
AB2 = 4100
AB = 64.03
Therefore the required distance is 64.03 m.
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