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Question
From the given figure, find the length of hypotenuse AC and the perimeter of ∆ABC.
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Solution
Given here is a right-angled triangle. So, we can apply Pythagoras theorem.
AB2 + BC2 = AC2
⇒ 202 + 212 = AC2
⇒ AC2 = 400 + 441 = 841
⇒ AC = 29
Thus, the length of hypotenuse is 29 units.
Perimeter of ∆ABC = AB + BC + CA = 20 + 21 + 29 = 70 units.
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