Advertisements
Advertisements
प्रश्न
From the given figure, find the length of hypotenuse AC and the perimeter of ∆ABC.
Advertisements
उत्तर
Given here is a right-angled triangle. So, we can apply Pythagoras’s theorem.
AB2 + BC2 = AC2
⇒ 202 + 212 = AC2
⇒ AC2 = 400 + 441
= 841
⇒ AC = 29
Thus, the length of the hypotenuse is 29 units.
Perimeter of ∆ABC = AB + BC + CA =
20 + 21 + 29
= 70 units.
APPEARS IN
संबंधित प्रश्न
ABC is an isosceles triangle with AC = BC. If AB2 = 2AC2, prove that ABC is a right triangle.
A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.
The diagonals of a rhombus measure 16 cm and 30 cm. Find its perimeter.
Identify, with reason, if the following is a Pythagorean triplet.
(4, 9, 12)
In ∆PQR, point S is the midpoint of side QR. If PQ = 11, PR = 17, PS = 13, find QR.
In triangle ABC, angle A = 90o, CA = AB and D is the point on AB produced.
Prove that DC2 - BD2 = 2AB.AD.
In figure AB = BC and AD is perpendicular to CD.
Prove that: AC2 = 2BC. DC.
Show that the triangle ABC is a right-angled triangle; if: AB = 9 cm, BC = 40 cm and AC = 41 cm
A ladder 25m long reaches a window of a building 20m above the ground. Determine the distance of the foot of the ladder from the building.
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AC2 - AB2 = 2BC x ED
