Advertisements
Advertisements
प्रश्न
From the given figure, find the length of hypotenuse AC and the perimeter of ∆ABC.
Advertisements
उत्तर
Given here is a right-angled triangle. So, we can apply Pythagoras’s theorem.
AB2 + BC2 = AC2
⇒ 202 + 212 = AC2
⇒ AC2 = 400 + 441
= 841
⇒ AC = 29
Thus, the length of the hypotenuse is 29 units.
Perimeter of ∆ABC = AB + BC + CA =
20 + 21 + 29
= 70 units.
APPEARS IN
संबंधित प्रश्न
Prove that the sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals
In the following figure, O is a point in the interior of a triangle ABC, OD ⊥ BC, OE ⊥ AC and OF ⊥ AB. Show that
(i) OA2 + OB2 + OC2 − OD2 − OE2 − OF2 = AF2 + BD2 + CE2
(ii) AF2 + BD2 + CE2 = AE2 + CD2 + BF2
Which of the following can be the sides of a right triangle?
2 cm, 2 cm, 5 cm
In the case of right-angled triangles, identify the right angles.
Identify, with reason, if the following is a Pythagorean triplet.
(11, 60, 61)
In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.
O is any point inside a rectangle ABCD.
Prove that: OB2 + OD2 = OC2 + OA2.
In triangle ABC, ∠B = 90o and D is the mid-point of BC.
Prove that: AC2 = AD2 + 3CD2.
In the figure below, find the value of 'x'.
A flag pole 18 m high casts a shadow 9.6 m long. Find the distance of the top of the pole from the far end of the shadow.
In an isosceles triangle PQR, the length of equal sides PQ and PR is 13 cm and base QR is 10 cm. Find the length of perpendicular bisector drawn from vertex P to side QR.
