मराठी

A Man Goes 40 M Due North and Then 50 M Due West. Find His Distance from the Starting Point - Mathematics

Advertisements
Advertisements

प्रश्न

A man goes 40 m due north and then 50 m due west. Find his distance from the starting point.

बेरीज
Advertisements

उत्तर

Here, we need to measure the distance AB as shown in the figure below,

Pythagoras theorem states that in a right-angled triangle, the square on the hypotenuse is equal to the sum of the squares on the remaining two sides.

Therefore, in this case
AB2 = BC2 + CA
AB2 = 502 + 40
AB2 =  2500 + 1600
AB2 = 4100
AB = 64.03
Therefore the required distance is 64.03 m.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Pythagoras Theorem [Proof and Simple Applications with Converse] - Exercise 13 (A) [पृष्ठ १५८]

APPEARS IN

सेलिना Concise Mathematics [English] Class 9 ICSE
पाठ 13 Pythagoras Theorem [Proof and Simple Applications with Converse]
Exercise 13 (A) | Q 2 | पृष्ठ १५८

संबंधित प्रश्‍न

P and Q are the mid-points of the sides CA and CB respectively of a ∆ABC, right angled at C. Prove that:

`(i) 4AQ^2 = 4AC^2 + BC^2`

`(ii) 4BP^2 = 4BC^2 + AC^2`

`(iii) (4AQ^2 + BP^2 ) = 5AB^2`


In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that

`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`

`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`

`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`


In Figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC × BD


A ladder 10 m long reaches a window 8 m above the ground. Find the distance of the foot of the ladder from base of the wall.


Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.


Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of remaining two sides.


In the given figure, ∠DFE = 90°, FG ⊥ ED, If GD = 8, FG = 12, find (1) EG (2) FD and (3) EF


Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.


Digonals of parallelogram WXYZ intersect at point O. If OY =5, find WY.


In a quadrilateral ABCD, ∠B = 90° and ∠D = 90°.
Prove that: 2AC2 - AB2 = BC2 + CD2 + DA2


M andN are the mid-points of the sides QR and PQ respectively of a PQR, right-angled at Q.
Prove that:
(i) PM2 + RN2 = 5 MN2
(ii) 4 PM2 = 4 PQ2 + QR2
(iii) 4 RN2 = PQ2 + 4 QR2(iv) 4 (PM2 + RN2) = 5 PR2


Choose the correct alternative: 

In right-angled triangle PQR, if hypotenuse PR = 12 and PQ = 6, then what is the measure of ∠P? 


Find the Pythagorean triplet from among the following set of numbers.

3, 4, 5


Find the Pythagorean triplet from among the following set of numbers.

4, 5, 6


Find the Pythagorean triplet from among the following set of numbers.

2, 6, 7


Find the length of the perpendicular of a triangle whose base is 5cm and the hypotenuse is 13cm. Also, find its area.


Each side of rhombus is 10cm. If one of its diagonals is 16cm, find the length of the other diagonals.


To get from point A to point B you must avoid walking through a pond. You must walk 34 m south and 41 m east. To the nearest meter, how many meters would be saved if it were possible to make a way through the pond?


In the figure, find AR


Prove that the area of the equilateral triangle drawn on the hypotenuse of a right angled triangle is equal to the sum of the areas of the equilateral triangles drawn on the other two sides of the triangle.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×