English

Calculate the Area of a Right-angled Triangle Whose Hypotenuse is 65cm and One Side is 16cm. - Mathematics

Advertisements
Advertisements

Question

Calculate the area of a right-angled triangle whose hypotenuse is 65cm and one side is 16cm.

Sum
Advertisements

Solution

Hypotenuse = 65cm
One side = 16cm
Let the other side be of length x cm
By Pythagoras theorem,
(65cm)2 = (16cm)2 + (x cm)2
(x cm)2 = 4225cm2 - 256cm2
= 3969cm2
= (63cm)2
⇒ x = 63cm
Area of the triangle
= `(1)/(2) xx ("Base" xx "Height")`

= `(1)/(2) xx 16"cm" xx 63"cm"`
= 504cm2.

shaalaa.com
  Is there an error in this question or solution?
Chapter 17: Pythagoras Theorem - Exercise 17.1

APPEARS IN

Frank Mathematics [English] Class 9 ICSE
Chapter 17 Pythagoras Theorem
Exercise 17.1 | Q 3

RELATED QUESTIONS

Prove that the diagonals of a rectangle ABCD, with vertices A(2, -1), B(5, -1), C(5, 6) and D(2, 6), are equal and bisect each other.


A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 2.5 m away from the wall, find the length of the ladder


PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.


In the given figure, ∆ABC is an equilateral triangle of side 3 units. Find the coordinates of the other two vertices ?


In the figure: ∠PSQ = 90o, PQ = 10 cm, QS = 6 cm and RQ = 9 cm. Calculate the length of PR.


In the given figure, BL and CM are medians of a ∆ABC right-angled at A. Prove that 4 (BL2 + CM2) = 5 BC2.


The sides of a certain triangle is given below. Find, which of them is right-triangle

6 m, 9 m, and 13 m


In the figure below, find the value of 'x'.


In the right-angled ∆LMN, ∠M = 90°. If l(LM) = 12 cm and l(LN) = 20 cm, find the length of seg MN.


The sides of the triangle are given below. Find out which one is the right-angled triangle?

11, 60, 61


Find the length of the perpendicular of a triangle whose base is 5cm and the hypotenuse is 13cm. Also, find its area.


In ΔABC, AD is perpendicular to BC. Prove that: AB2 + CD2 = AC2 + BD2


In an equilateral triangle ABC, the side BC is trisected at D. Prove that 9 AD2 = 7 AB2.


To get from point A to point B you must avoid walking through a pond. You must walk 34 m south and 41 m east. To the nearest meter, how many meters would be saved if it were possible to make a way through the pond?


The perpendicular PS on the base QR of a ∆PQR intersects QR at S, such that QS = 3 SR. Prove that 2PQ2 = 2PR2 + QR2 


For going to a city B from city A, there is a route via city C such that AC ⊥ CB, AC = 2x km and CB = 2(x + 7) km. It is proposed to construct a 26 km highway which directly connects the two cities A and B. Find how much distance will be saved in reaching city B from city A after the construction of the highway.


In figure, PQR is a right triangle right angled at Q and QS ⊥ PR. If PQ = 6 cm and PS = 4 cm, find QS, RS and QR.


If two legs of a right triangle are equal to two legs of another right triangle, then the right triangles are congruent.


Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place?


The foot of a ladder is 6 m away from its wall and its top reaches a window 8 m above the ground. Find the length of the ladder.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×