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In a Right-angled Triangle Abc,Abc = 90°, Ac = 10 Cm, Bc = 6 Cm and Bc Produced to D Such Cd = 9 Cm. Find the Length of Ad.

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Question

In a right-angled triangle ABC,ABC = 90°, AC = 10 cm, BC = 6 cm and BC produced to D such CD = 9 cm. Find the length of AD.

Sum
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Solution


In ΔABC, ∠B = 90°
∴  AC2 = AB2 + BC    ....(Pythagoras Theorem)
⇒ 102 = AB2 + 62
⇒ AB2 = 102 - 62
= 100 - 36
= 64
Now,
BD = BC + CD
= 6 + 9
= 15cm
⇒ BD2 = 225
In ΔABD, ∠B = 90°
∴ AD2 = AB2 + BD2
⇒ AD2 = 64 + 225 = 289
⇒ AD = 17cm.

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Chapter 12: Pythagoras Theorem - Exercise 17.1

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Frank Mathematics Part 1 [English] Class 9 ICSE
Chapter 12 Pythagoras Theorem
Exercise 17.1 | Q 22

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