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Question
Find the length diagonal of a rectangle whose length is 35 cm and breadth is 12 cm.
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Solution
`square`ABCD is a rectangle
`l(AB) = 35 cm`
`l(BC) = 12 cm`
Let AC be the diagonal of rectangle
as ∠A = ∠B = ∠C = ∠D = 90°
∴ In `triangle`ABC, as ∠B = 90°
∴ By using Pythagoras theorem.
`AC^2 = AB^2 + BC^2`
`AC^2 = 35^2 + 12^2`
`AC^2 = 1225 + 144`
`AC^2 =1369`
`AC =37cm`
∴ The diagonal of the rectangle is 37 cm.
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