Advertisements
Advertisements
Question
There are two paths that one can choose to go from Sarah’s house to James's house. One way is to take C street, and the other way requires to take B street and then A street. How much shorter is the direct path along C street?
Advertisements
Solution
Distance between Sarah’s House and James’s House using “C street”.
AC2 = AB2 + BC2
= 22 + 1.52
= 4 + 2.25
= 6.25
AC = `sqrt(6.25)`
AC = 2.5 miles
Distance covered by using “A Street” and “B Street”
= (2 + 1.5) miles
= 3.5 miles
Difference in distance = 3.5 miles – 2.5 miles = 1 mile
APPEARS IN
RELATED QUESTIONS
In Figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AD2 = BD × CD
Identify, with reason, if the following is a Pythagorean triplet.
(10, 24, 27)
In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)
In the given figure, AB//CD, AB = 7 cm, BD = 25 cm and CD = 17 cm;
find the length of side BC.
In the figure, given below, AD ⊥ BC.
Prove that: c2 = a2 + b2 - 2ax.
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
In the given figure, PQ = `"RS"/(3)` = 8cm, 3ST = 4QT = 48cm.
SHow that ∠RTP = 90°.
To get from point A to point B you must avoid walking through a pond. You must walk 34 m south and 41 m east. To the nearest meter, how many meters would be saved if it were possible to make a way through the pond?
In a right angled triangle, if length of hypotenuse is 25 cm and height is 7 cm, then what is the length of its base?
In figure, PQR is a right triangle right angled at Q and QS ⊥ PR. If PQ = 6 cm and PS = 4 cm, find QS, RS and QR.
