Advertisements
Advertisements
प्रश्न
There are two paths that one can choose to go from Sarah’s house to James's house. One way is to take C street, and the other way requires to take B street and then A street. How much shorter is the direct path along C street?

Advertisements
उत्तर
Distance between Sarah’s House and James’s House using “C street”.
AC2 = AB2 + BC2
= 22 + 1.52
= 4 + 2.25
= 6.25
AC = `sqrt(6.25)`
AC = 2.5 miles
Distance covered by using “A Street” and “B Street”
= (2 + 1.5) miles
= 3.5 miles
Difference in distance = 3.5 miles – 2.5 miles = 1 mile
APPEARS IN
संबंधित प्रश्न
In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that
`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`
`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`
`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`
Two poles of heights 6 m and 11 m stand on a plane ground. If the distance between the feet of the poles is 12 m, find the distance between their tops.
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
If the angles of a triangle are 30°, 60°, and 90°, then shown that the side opposite to 30° is half of the hypotenuse, and the side opposite to 60° is `sqrt(3)/2` times of the hypotenuse.
Prove that in a right angle triangle, the square of the hypotenuse is equal to the sum of squares of the other two sides.
The top of a ladder of length 15 m reaches a window 9 m above the ground. What is the distance between the base of the wall and that of the ladder?
A ladder 15m long reaches a window which is 9m above the ground on one side of a street. Keeping its foot at the same point, the ladder is turned to other side of the street to reach a window 12m high. Find the width of the street.
AD is perpendicular to the side BC of an equilateral ΔABC. Prove that 4AD2 = 3AB2.
Find the unknown side in the following triangles
The longest side of a right angled triangle is called its ______.
