Advertisements
Advertisements
Question
Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
Advertisements
Solution
The given set of numbers is (9, 40, 41).
We use the Pythagorean theorem:
Hypotenuse2 = Base2 + Height2
∴ 412 = 92 + 402
1681 = 81 + 1600
∴ 412 = 1681
Since 412= 1681, the Pythagorean theorem holds true.
Thus, (9, 40, 41) forms a Pythagorean triplet.
RELATED QUESTIONS
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
A guy wire attached to a vertical pole of height 18 m is 24 m long and has a stake attached to the other end. How far from the base of the pole should the stake be driven so that the wire will be taut?
The given figure shows a quadrilateral ABCD in which AD = 13 cm, DC = 12 cm, BC = 3 cm and ∠ABD = ∠BCD = 90o. Calculate the length of AB.
Find the length of diagonal of the square whose side is 8 cm.
Triangle XYZ is right-angled at vertex Z. Calculate the length of YZ, if XY = 13 cm and XZ = 12 cm.
A ladder 25m long reaches a window of a building 20m above the ground. Determine the distance of the foot of the ladder from the building.
A point OI in the interior of a rectangle ABCD is joined with each of the vertices A, B, C and D. Prove that OB2 + OD2 = OC2 + OA2
From given figure, In ∆ABC, If AC = 12 cm, then AB = ?

Activity: From given figure, In ∆ABC, ∠ABC = 90°, ∠ACB = 30°
∴ ∠BAC = `square`
∴ ∆ABC is 30° – 60° – 90° triangle.
∴ In ∆ABC by property of 30° – 60° – 90° triangle.
∴ AB = `1/2` AC and `square` = `sqrt(3)/2` AC
∴ `square` = `1/2 xx 12` and BC = `sqrt(3)/2 xx 12`
∴ `square` = 6 and BC = `6sqrt(3)`
In ΔABC, if DE || BC, AD = x, DB = x – 2, AE = x + 2 and EC = x – 1, then value of x is ______.
In a right-angled triangle ABC, if angle B = 90°, then which of the following is true?
