Advertisements
Advertisements
प्रश्न
Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
Advertisements
उत्तर
The given set of numbers is (9, 40, 41).
We use the Pythagorean theorem:
Hypotenuse2 = Base2 + Height2
∴ 412 = 92 + 402
1681 = 81 + 1600
∴ 412 = 1681
Since 412= 1681, the Pythagorean theorem holds true.
Thus, (9, 40, 41) forms a Pythagorean triplet.
संबंधित प्रश्न
The perpendicular from A on side BC of a Δ ABC intersects BC at D such that DB = 3CD . Prove that 2AB2 = 2AC2 + BC2.
Identify, with reason, if the following is a Pythagorean triplet.
(5, 12, 13)
In ∆PQR, point S is the midpoint of side QR. If PQ = 11, PR = 17, PS = 13, find QR.
Digonals of parallelogram WXYZ intersect at point O. If OY =5, find WY.
In ΔMNP, ∠MNP = 90˚, seg NQ ⊥ seg MP, MQ = 9, QP = 4, find NQ.
Choose the correct alternative:
In right-angled triangle PQR, if hypotenuse PR = 12 and PQ = 6, then what is the measure of ∠P?
A boy first goes 5 m due north and then 12 m due east. Find the distance between the initial and the final position of the boy.
In a square PQRS of side 5 cm, A, B, C and D are points on sides PQ, QR, RS and SP respectively such as PA = PD = RB = RC = 2 cm. Prove that ABCD is a rectangle. Also, find the area and perimeter of the rectangle.
In a right angled triangle, the hypotenuse is the greatest side
If length of sides of a triangle are a, b, c and a2 + b2 = c2, then which type of triangle it is?
