Advertisements
Advertisements
प्रश्न
Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
Advertisements
उत्तर
The given set of numbers is (9, 40, 41).
We use the Pythagorean theorem:
Hypotenuse2 = Base2 + Height2
∴ 412 = 92 + 402
1681 = 81 + 1600
∴ 412 = 1681
Since 412= 1681, the Pythagorean theorem holds true.
Thus, (9, 40, 41) forms a Pythagorean triplet.
संबंधित प्रश्न
A man goes 10 m due east and then 24 m due north. Find the distance from the starting point
Sides of triangle are given below. Determine it is a right triangle or not? In case of a right triangle, write the length of its hypotenuse. 50 cm, 80 cm, 100 cm
PQR is a triangle right angled at P and M is a point on QR such that PM ⊥ QR. Show that PM2 = QM . MR
Prove that, in a right-angled triangle, the square of the hypotenuse is equal to the sum of the square of remaining two sides.
ABC is a triangle, right-angled at B. M is a point on BC.
Prove that: AM2 + BC2 = AC2 + BM2
In the figure below, find the value of 'x'.

Sides AB and BE of a right triangle, right-angled at B are of lengths 16 cm and 8 cm respectively. The length of the side of largest square FDGB that can be inscribed in the triangle ABE is ______.

The top of a broken tree touches the ground at a distance of 12 m from its base. If the tree is broken at a height of 5 m from the ground then the actual height of the tree is ______.
If the areas of two circles are the same, they are congruent.
Jiya walks 6 km due east and then 8 km due north. How far is she from her starting place?
