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प्रश्न
Find the Pythagorean triplet from among the following set of numbers.
9, 40, 41
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उत्तर
The given set of numbers is (9, 40, 41).
We use the Pythagorean theorem:
Hypotenuse2 = Base2 + Height2
∴ 412 = 92 + 402
1681 = 81 + 1600
∴ 412 = 1681
Since 412= 1681, the Pythagorean theorem holds true.
Thus, (9, 40, 41) forms a Pythagorean triplet.
संबंधित प्रश्न
In a right triangle ABC right-angled at C, P and Q are the points on the sides CA and CB respectively, which divide these sides in the ratio 2 : 1. Prove that
`(i) 9 AQ^2 = 9 AC^2 + 4 BC^2`
`(ii) 9 BP^2 = 9 BC^2 + 4 AC^2`
`(iii) 9 (AQ^2 + BP^2 ) = 13 AB^2`
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