Advertisements
Advertisements
प्रश्न
For finding AB and BC with the help of information given in the figure, complete following activity.
AB = BC .......... 
∴ ∠BAC =
∴ AB = BC = × AC
= × `sqrt8`
= × `2sqrt2`
=
Advertisements
उत्तर
AB = BC ...(Given)
∴ ∠BAC = 45°
∴ AB = BC = `1/sqrt2` × AC
= `1/sqrt2` × `sqrt8`
= `1/sqrt2` × `2sqrt2`
= 2
संबंधित प्रश्न
ABCD is a rhombus. Prove that AB2 + BC2 + CD2 + DA2= AC2 + BD2
PQR is a triangle right angled at P. If PQ = 10 cm and PR = 24 cm, find QR.
Find the side and perimeter of a square whose diagonal is 10 cm.
In ∆ABC, AB = 10, AC = 7, BC = 9, then find the length of the median drawn from point C to side AB.
In ∆ABC, seg AD ⊥ seg BC, DB = 3CD.
Prove that: 2AB2 = 2AC2 + BC2
Digonals of parallelogram WXYZ intersect at point O. If OY =5, find WY.
If the sides of the triangle are in the ratio 1: `sqrt2`: 1, show that is a right-angled triangle.
M andN are the mid-points of the sides QR and PQ respectively of a PQR, right-angled at Q.
Prove that:
(i) PM2 + RN2 = 5 MN2
(ii) 4 PM2 = 4 PQ2 + QR2
(iii) 4 RN2 = PQ2 + 4 QR2(iv) 4 (PM2 + RN2) = 5 PR2
Find the side of the square whose diagonal is `16sqrt(2)` cm.
In the figure below, find the value of 'x'.
The top of a ladder of length 15 m reaches a window 9 m above the ground. What is the distance between the base of the wall and that of the ladder?
Find the Pythagorean triplet from among the following set of numbers.
2, 4, 5
Find the Pythagorean triplet from among the following set of numbers.
2, 6, 7
Find the Pythagorean triplet from among the following set of numbers.
4, 7, 8
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AC2 = AD2 + BC x DE + `(1)/(4)"BC"^2`
In a triangle ABC, AC > AB, D is the midpoint BC, and AE ⊥ BC. Prove that: AB2 + AC2 = 2AD2 + `(1)/(2)"BC"^2`
An isosceles triangle has equal sides each 13 cm and a base 24 cm in length. Find its height
Find the length of the support cable required to support the tower with the floor
From the given figure, in ∆ABQ, if AQ = 8 cm, then AB =?
If the areas of two circles are the same, they are congruent.
