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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

A man goes 18 m due east and then 24 m due north. Find the distance of his current position from the starting point?

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प्रश्न

A man goes 18 m due east and then 24 m due north. Find the distance of his current position from the starting point?

योग
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उत्तर

Let the initial position of the man be “O” and his final position be “B”.

By Pythagoras theorem

In the right ∆OAB,

OB2 = OA2 + AB2

= 182 + 242

= 324 + 576 = 900

OB = `sqrt(900)` = 30

The distance of his current position is 30 m

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अध्याय 4: Geometry - Exercise 4.3 [पृष्ठ १८७]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 4 Geometry
Exercise 4.3 | Q 1 | पृष्ठ १८७

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