Advertisements
Advertisements
प्रश्न
A man goes 18 m due east and then 24 m due north. Find the distance of his current position from the starting point?
Advertisements
उत्तर
Let the initial position of the man be “O” and his final position be “B”.
By Pythagoras theorem
In the right ∆OAB,
OB2 = OA2 + AB2
= 182 + 242
= 324 + 576 = 900
OB = `sqrt(900)` = 30
The distance of his current position is 30 m
APPEARS IN
संबंधित प्रश्न
In Figure, ABD is a triangle right angled at A and AC ⊥ BD. Show that AB2 = BC × BD
In an equilateral triangle ABC, D is a point on side BC such that BD = `1/3BC` . Prove that 9 AD2 = 7 AB2
In the given figure, ∆ABC is an equilateral triangle of side 3 units. Find the coordinates of the other two vertices ?
Walls of two buildings on either side of a street are parallel to each other. A ladder 5.8 m long is placed on the street such that its top just reaches the window of a building at the height of 4 m. On turning the ladder over to the other side of the street, its top touches the window of the other building at a height 4.2 m. Find the width of the street.
In a trapezium ABCD, seg AB || seg DC seg BD ⊥ seg AD, seg AC ⊥ seg BC, If AD = 15, BC = 15 and AB = 25. Find A(▢ABCD)
In the given figure, angle ACP = ∠BDP = 90°, AC = 12 m, BD = 9 m and PA= PB = 15 m. Find:
(i) CP
(ii) PD
(iii) CD
In a triangle ABC right angled at C, P and Q are points of sides CA and CB respectively, which divide these sides the ratio 2 : 1.
Prove that: 9BP2 = 9BC2 + 4AC2
In the given figure, ∠T and ∠B are right angles. If the length of AT, BC and AS (in centimeters) are 15, 16, and 17 respectively, then the length of TC (in centimeters) is ______.
Two rectangles are congruent, if they have same ______ and ______.
The hypotenuse (in cm) of a right angled triangle is 6 cm more than twice the length of the shortest side. If the length of third side is 6 cm less than thrice the length of shortest side, then find the dimensions of the triangle.
