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Find the Equation to the Straight Line Which Cuts off Equal Positive Intercepts on the Axes and Their Product is 25.

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Question

Find the equation to the straight line which cuts off equal positive intercepts on the axes and their product is 25.

Answer in Brief
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Solution

The equation of the line with intercepts a and b is \[\frac{x}{a} + \frac{y}{b} = 1\].

Here, a = b and ab = 25

\[\therefore a \times a = 25\]

\[ \Rightarrow a^2 = 25\]

\[ \Rightarrow a = 5 \left( \because \text { we are to take only positive value of intercepts } \right)\]

Hence, the equation of the required line is

\[\frac{x}{5} + \frac{y}{5} = 1\] 

 \[ \Rightarrow x + y = 5\]
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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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Chapter 23: The straight lines - Exercise 23.6 [Page 47]

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R.D. Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.6 | Q 5 | Page 47

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