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Question
Find the equation of the line which passes through the point (3, 4) and is such that the portion of it intercepted between the axes is divided by the point in the ratio 2:3.
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Solution
The equation of the line with intercepts a and b is \[\frac{x}{a} + \frac{y}{b} = 1\] .Since the line meets the coordinate axes at A and B, the coordinates are A (a, 0) and B (0, b).
Let the given point be P (3, 4).
Here,
\[AP : BP = 2 : 3\]
\[\therefore 3 = \frac{2 \times 0 + 3 \times a}{2 + 3}, 4 = \frac{2 \times b + 3 \times 0}{2 + 3}\]
\[ \Rightarrow 3a = 15, 2b = 20\]
\[ \Rightarrow a = 5, b = 10\]
Hence, the equation of the line is
\[\frac{x}{5} + \frac{y}{10} = 1\]
\[ \Rightarrow 2x + y = 10\]
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