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The Equation of the Straight Line Which Passes Through the Point (−4, 3) Such that the Portion of the Line Between the Axes is Divided Internally by the Point in the Ratio 5 : 3 is

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Question

The equation of the straight line which passes through the point (−4, 3) such that the portion of the line between the axes is divided internally by the point in the ratio 5 : 3 is

Options

  • 9x − 20y + 96 = 0

  •  9x + 20y = 24

  •  20x + 9y + 53 = 0

  • none of these

MCQ
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Solution

9x − 20y + 96 = 0

Let the required line intersects the coordinate axis at (a, 0) and (0, b).

The point (−4, 3) divides the required line in the ratio 5 : 3

\[\therefore - 4 = \frac{5 \times 0 + 3 \times a}{5 + 3} \text { and } 3 = \frac{5 \times b + 3 \times 0}{5 + 3}\]

\[ \Rightarrow a = \frac{- 32}{3} \text { and } b = \frac{24}{5}\]

Hence, The equation of the required line is given below:

\[\frac{x}{\frac{- 32}{3}} + \frac{y}{\frac{24}{5}} = 1\]

\[ \Rightarrow \frac{- 3x}{32} + \frac{5y}{24} = 1\]

\[ \Rightarrow - 9x + 20y = 96\]

\[ \Rightarrow 9x - 20y + 96 = 0\]

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Equations of Line in Different Forms - Equation of Family of Lines Passing Through the Point of Intersection of Two Lines
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Chapter 23: The straight lines - Exercise 23.21 [Page 133]

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R.D. Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.21 | Q 4 | Page 133

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