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Find the Equation of the Right Bisector of the Line Segment Joining the Points (3, 4) and (−1, 2).

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Question

Find the equation of the right bisector of the line segment joining the points (3, 4) and (−1, 2).

Answer in Brief
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Solution

Let A (3, 4) and B (−1, 2) be the given points.
Let C be the midpoint of AB.

\[\therefore C \equiv \left( \frac{3 - 1}{2}, \frac{4 + 2}{2} \right) \equiv \left( 1, 3 \right)\]

\[\because \text { Slope of AB } = \frac{2 - 4}{- 1 - 3} = \frac{1}{2}\]

\[ \therefore \text { Slope of the perpendicular bisector of AB } = - 2\]

Thus, the equation of the perpendicular bisector of AB is

\[y - 3 = - 2\left( x - 1 \right)\]

\[ \Rightarrow 2x + y - 5 = 0\]

Hence, the required line is \[2x + y - 5 = 0\].

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Chapter 23: The straight lines - Exercise 23.12 [Page 93]

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R.D. Sharma Mathematics [English] Class 11
Chapter 23 The straight lines
Exercise 23.12 | Q 18 | Page 93

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