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Question
Find the equation of a straight line with slope − 1/3 and y-intercept − 4.
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Solution
Here, \[m = - \frac{1}{3}, c = - 4\]
Substituting the values of m and c in y = mx + c, we get,
\[y = - \frac{x}{3} - 4\]
\[ \Rightarrow x + 3y + 12 = 0\]
Hence, the equation of the straight line with slope
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| (d) Equally inclined to the axes is | (iv) 3x – 4y – 1 = 0 |
