English

Explain the Trends in the Following Properties with Reference to Group 16

Advertisements
Advertisements

Question

a. Explain the trends in the following properties with reference to group 16:

1 Atomic radii and ionic radii

2 Density

3 ionisation enthalpy

4 Electronegativity

b. In the electolysis of AgNO3 solution 0.7g of Ag is deposited after a certain period of time. Calulate the quantity of electricity required in coulomb. (Molar mass of Ag is 107.9g mol-1)

 

Advertisements

Solution

(a) Trends in 16-Group

(i) Atomic radii and ionic radii
Down the group atomic radii increases.

(ii) Density
Down the group density increased.

(iii) Ionization enthalpy
The Ist ionization enthapies of the elements of group 16 are unexpectedly lower, while their IInd ionization enthalpies are higher than those of the correspending element of group 15.

(iv) Electronegativity
The element of group 16 have higher value of electronegativity then the corresponding element of group 15.

(b) `"Mass of sub"=Q/96500xx"mole ratio"xx"mol mass"`

Mass of sub = 0.7 g

`"Mole ratio"=1/1`

Molar mass = 107.9

`:.0.7=Q/96500xx1xx107.9`

`Q=(0.7xx96500)/107.9`

`=67550/107.9`

=626.04

Quantity of electricity = 626.04 C

 

shaalaa.com
  Is there an error in this question or solution?
2012-2013 (March)

APPEARS IN

RELATED QUESTIONS

Account for the following: Oxygen shows catenation behavior less than sulphur.


Give reasons: SO2 is reducing while TeO2 is an oxidising agent.


Account for the following : There is large difference between the melting and boiling points of oxygen and sulphur.


Give reasons for the following : H2Te is the strongest reducing agent amongst all the hydrides of Group 16 elements.


Give reasons for the following : Oxygen has less electron gain enthalpy with negative sign than sulphur.


List the important sources of sulphur.


Why does NH3 form hydrogen bond but PH3 does not?


The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp3 hybridisation in NH3 and only s−p bonding between hydrogen and other elements of the group].


Justify the placement of O, S, Se, Te and Po in the same group of the periodic table in terms of electronic configuration, oxidation state and hydride formation.


Explain why inspite of nearly the same electronegativity, oxygen forms hydrogen bonding while chlorine does not.


Arrange the following in the order of the property indicated against set :
H2O, H2S, H2Se, H2Te − increasing acidic character.


Explain the following properties of group 16 elements :
1) Electro negativity
2) Melting and boiling points
3) Metallic character
4) Allotropy


 Give reactions for the following: 
O – O single bond is weaker than S – S single bond. 


Arrange the following in order of the property indicated set.
HF, HCl, HBr, HI - decreasing bond enthalpy.


The formation of \[\ce{O^+_2[PtF6]^-}\] is the basis for the formation of first xenon compound. This is because ____________.


Which of the following statement is incorrect?


Match the items of Columns I and II and mark the correct option.

Column I Column II
(A) \[\ce{H2SO4}\] (1) Highest electron gain enthalpy
(B) \[\ce{CCl3NO2}\] (2) Chalcogen
(C) \[\ce{Cl2}\] (3) Tear gas
(D) Sulphur (4) Storage batteries

In forming (i) \[\ce{N2 -> N^{+}2}\] and (ii) \[\ce{O2 -> O^{+}2}\]; the electrons respectively are removed from:


Which of the following compound is a peroxide?


These are physical properties of an elements.

  1. Sublimation enthalpy
  2. Ionisation enthalpy
  3. Hydration enthalpy
  4. Electron gain enthalpy

The total number of above properties that affect the reduction potential is ______. (Integer answer)


What is the basicity of \[\ce{H3PO4}\]?


______ is a radioactive element in group 16 elements.


______ is a gaseous element of group 16.


Given below are two statements:

Statement I: The boiling point of hydrides of Group 16 elements follows the order:

H2O > H2Te > H2Se > H2S

Statement II: On the basis of molecular mass, H2O is expected to have a lower boiling point than the other members of the group but due to the presence of extensive H-bonding in H2O, it has a higher boiling point.

In the light of the above statements, choose the correct answer from the options given below:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×