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Question
Out of \[\ce{H2O}\] and \[\ce{H2S}\], which one has higher bond angle and why?
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Solution
Oxygen is more electronegative than sulphur, the bond angle of \[\ce{H2O}\] is greater, and the body pair electron of an \[\ce{OH}\] bond will be closer to oxygen, causing bond-pair bond-pair repulsion between bond pairs of two \[\ce{OH}\] bonds.
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